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x-0.25x^2-0.2375=0
a = -0.25; b = 1; c = -0.2375;
Δ = b2-4ac
Δ = 12-4·(-0.25)·(-0.2375)
Δ = 0.7625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{0.7625}}{2*-0.25}=\frac{-1-\sqrt{0.7625}}{-0.5} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{0.7625}}{2*-0.25}=\frac{-1+\sqrt{0.7625}}{-0.5} $
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